Solve 5-ay-(-4a)*(5-a)^2=

$$5 - a y - ( - 4 a ) \cdot ( 5 - a ) ^ { 2 } =$$

Evaluate

$$4a\left(5-a\right)^{2}-ay+5$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(5-a\right)^{2}.

$$5-ay-\left(-4a\left(25-10a+a^{2}\right)\right)$$

The opposite of -4a\left(25-10a+a^{2}\right) is 4a\left(25-10a+a^{2}\right).

$$5-ay+4a\left(25-10a+a^{2}\right)$$

Use the distributive property to multiply 4a by 25-10a+a^{2}.

$$5-ay+100a-40a^{2}+4a^{3}$$

Expand

$$5+100a-40a^{2}+4a^{3}-ay$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(5-a\right)^{2}.

$$5-ay-\left(-4a\left(25-10a+a^{2}\right)\right)$$

The opposite of -4a\left(25-10a+a^{2}\right) is 4a\left(25-10a+a^{2}\right).

$$5-ay+4a\left(25-10a+a^{2}\right)$$

Use the distributive property to multiply 4a by 25-10a+a^{2}.

$$5-ay+100a-40a^{2}+4a^{3}$$