Solve 5-3tx=2x

$$5 - 3 t x = 2 x$$

Solve for t

$$t=-\frac{2}{3}+\frac{5}{3x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 5 from both sides.

$$-3tx=2x-5$$

The equation is in standard form.

$$\left(-3x\right)t=2x-5$$

Divide both sides by -3x.

$$\frac{\left(-3x\right)t}{-3x}=\frac{2x-5}{-3x}$$

Dividing by -3x undoes the multiplication by -3x.

$$t=\frac{2x-5}{-3x}$$

Divide 2x-5 by -3x.

$$t=-\frac{2}{3}+\frac{5}{3x}$$

Solve for x

$$x=\frac{5}{3t+2}$$

$$t\neq -\frac{2}{3}$$

Steps for Solving Linear Equation

Subtract 2x from both sides.

$$5-3tx-2x=0$$

Subtract 5 from both sides. Anything subtracted from zero gives its negation.

$$-3tx-2x=-5$$

Combine all terms containing x.

$$\left(-3t-2\right)x=-5$$

Divide both sides by -3t-2.

$$\frac{\left(-3t-2\right)x}{-3t-2}=-\frac{5}{-3t-2}$$

Dividing by -3t-2 undoes the multiplication by -3t-2.

$$x=-\frac{5}{-3t-2}$$

Divide -5 by -3t-2.

$$x=\frac{5}{3t+2}$$