Solve 5-3(n*-7)geq(n*3)2

$$5 - 3 ( n \times - 7 ) \geq ( n \times 3 ) 2$$

Solve for n

$$n\geq -\frac{1}{3}$$

Solution Steps

Multiply 3 and -7 to get -21.

$$5-\left(-21n\right)\geq n\times 3\times 2$$

The opposite of -21n is 21n.

$$5+21n\geq n\times 3\times 2$$

Multiply 3 and 2 to get 6.

$$5+21n\geq n\times 6$$

Subtract n\times 6 from both sides.

$$5+21n-n\times 6\geq 0$$

Combine 21n and -n\times 6 to get 15n.

$$5+15n\geq 0$$

Subtract 5 from both sides. Anything subtracted from zero gives its negation.

$$15n\geq -5$$

Divide both sides by 15. Since 15 is positive, the inequality direction remains the same.

$$n\geq \frac{-5}{15}$$

Reduce the fraction \frac{-5}{15} to lowest terms by extracting and canceling out 5.

$$n\geq -\frac{1}{3}$$