Solve 5-3(4-2)-3+(6-2)*sqrt{4}+2

$$5 - 3 ( 4 - 2 ) - 3 + ( 6 - 2 ) \cdot \sqrt { 4 } + 2$$

Evaluate

$$6$$

Solution Steps

Subtract 2 from 4 to get 2.

$$5-3\times 2-3+\left(6-2\right)\sqrt{4}+2$$

Multiply 3 and 2 to get 6.

$$5-6-3+\left(6-2\right)\sqrt{4}+2$$

Subtract 6 from 5 to get -1.

$$-1-3+\left(6-2\right)\sqrt{4}+2$$

Subtract 3 from -1 to get -4.

$$-4+\left(6-2\right)\sqrt{4}+2$$

Subtract 2 from 6 to get 4.

$$-4+4\sqrt{4}+2$$

Calculate the square root of 4 and get 2.

$$-4+4\times 2+2$$

Multiply 4 and 2 to get 8.

$$-4+8+2$$

Add -4 and 8 to get 4.

$$4+2$$

Add 4 and 2 to get 6.

$$6$$

Factor

$$2\times 3$$