Solve 5-2*[-3-4*(-5+2)-2*(5-2):3]=

$$5 - 2 \cdot [ - 3 - 4 \cdot ( - 5 + 2 ) - 2 \cdot ( 5 - 2 ) : 3 ] =$$

Evaluate

$$-9$$

Solution Steps

Add -5 and 2 to get -3.

$$5-2\left(-3-4\left(-3\right)-\frac{2\left(5-2\right)}{3}\right)$$

Multiply 4 and -3 to get -12.

$$5-2\left(-3-\left(-12\right)-\frac{2\left(5-2\right)}{3}\right)$$

The opposite of -12 is 12.

$$5-2\left(-3+12-\frac{2\left(5-2\right)}{3}\right)$$

Add -3 and 12 to get 9.

$$5-2\left(9-\frac{2\left(5-2\right)}{3}\right)$$

Subtract 2 from 5 to get 3.

$$5-2\left(9-\frac{2\times 3}{3}\right)$$

Multiply 2 and 3 to get 6.

$$5-2\left(9-\frac{6}{3}\right)$$

Divide 6 by 3 to get 2.

$$5-2\left(9-2\right)$$

Subtract 2 from 9 to get 7.

$$5-2\times 7$$

Multiply 2 and 7 to get 14.

$$5-14$$

Subtract 14 from 5 to get -9.

$$-9$$

Factor

$$-9$$