Solve 5-2{3-5+6(3+1)^2+6-6div2}+4

$$5 - 2 \{ 3 - 5 + 6 ( 3 + 1 ) ^ { 2 } + 6 - 6 \div 2 \} + 4$$

Evaluate

$$-185$$

Solution Steps

Subtract 5 from 3 to get -2.

$$5-2\left(-2+6\left(3+1\right)^{2}+6-\frac{6}{2}\right)+4$$

Add 3 and 1 to get 4.

$$5-2\left(-2+6\times 4^{2}+6-\frac{6}{2}\right)+4$$

Calculate 4 to the power of 2 and get 16.

$$5-2\left(-2+6\times 16+6-\frac{6}{2}\right)+4$$

Multiply 6 and 16 to get 96.

$$5-2\left(-2+96+6-\frac{6}{2}\right)+4$$

Add -2 and 96 to get 94.

$$5-2\left(94+6-\frac{6}{2}\right)+4$$

Add 94 and 6 to get 100.

$$5-2\left(100-\frac{6}{2}\right)+4$$

Divide 6 by 2 to get 3.

$$5-2\left(100-3\right)+4$$

Subtract 3 from 100 to get 97.

$$5-2\times 97+4$$

Multiply 2 and 97 to get 194.

$$5-194+4$$

Subtract 194 from 5 to get -189.

$$-189+4$$

Add -189 and 4 to get -185.

$$-185$$

Factor

$$-185$$