Solve for x
x=12
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-\sqrt{3x}+6-6=-6
Subtract 6 from both sides of the equation.
-\sqrt{3x}=-6
Subtracting 6 from itself leaves 0.
\frac{-\sqrt{3x}}{-1}=-\frac{6}{-1}
Divide both sides by -1.
\sqrt{3x}=-\frac{6}{-1}
Dividing by -1 undoes the multiplication by -1.
\sqrt{3x}=6
Divide -6 by -1.
3x=36
Square both sides of the equation.
\frac{3x}{3}=\frac{36}{3}
Divide both sides by 3.
x=\frac{36}{3}
Dividing by 3 undoes the multiplication by 3.
x=12
Divide 36 by 3.
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