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\frac{15}{3}-\frac{1}{2}x+\frac{1}{3}=\frac{5}{4}
Convert 5 to fraction \frac{15}{3}.
\frac{15+1}{3}-\frac{1}{2}x=\frac{5}{4}
Since \frac{15}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.
\frac{16}{3}-\frac{1}{2}x=\frac{5}{4}
Add 15 and 1 to get 16.
-\frac{1}{2}x=\frac{5}{4}-\frac{16}{3}
Subtract \frac{16}{3} from both sides.
-\frac{1}{2}x=\frac{15}{12}-\frac{64}{12}
Least common multiple of 4 and 3 is 12. Convert \frac{5}{4} and \frac{16}{3} to fractions with denominator 12.
-\frac{1}{2}x=\frac{15-64}{12}
Since \frac{15}{12} and \frac{64}{12} have the same denominator, subtract them by subtracting their numerators.
-\frac{1}{2}x=-\frac{49}{12}
Subtract 64 from 15 to get -49.
x=-\frac{49}{12}\left(-2\right)
Multiply both sides by -2, the reciprocal of -\frac{1}{2}.
x=\frac{-49\left(-2\right)}{12}
Express -\frac{49}{12}\left(-2\right) as a single fraction.
x=\frac{98}{12}
Multiply -49 and -2 to get 98.
x=\frac{49}{6}
Reduce the fraction \frac{98}{12} to lowest terms by extracting and canceling out 2.