Solve 5(x-3)+4(x+5)=20quad(x-7)

$$5 ( x - 3 ) + 4 ( x + 5 ) = 20 \quad ( x - 7 )$$

Solve for x

$$x = \frac{145}{11} = 13\frac{2}{11} \approx 13.181818182$$

Steps for Solving Linear Equation

Use the distributive property to multiply 5 by x-3.

$$5x-15+4\left(x+5\right)=20\left(x-7\right)$$

Use the distributive property to multiply 4 by x+5.

$$5x-15+4x+20=20\left(x-7\right)$$

Combine 5x and 4x to get 9x.

$$9x-15+20=20\left(x-7\right)$$

Add -15 and 20 to get 5.

$$9x+5=20\left(x-7\right)$$

Use the distributive property to multiply 20 by x-7.

$$9x+5=20x-140$$

Subtract 20x from both sides.

$$9x+5-20x=-140$$

Combine 9x and -20x to get -11x.

$$-11x+5=-140$$

Subtract 5 from both sides.

$$-11x=-140-5$$

Subtract 5 from -140 to get -145.

$$-11x=-145$$

Divide both sides by -11.

$$x=\frac{-145}{-11}$$

Fraction \frac{-145}{-11} can be simplified to \frac{145}{11} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{145}{11}$$