Solve 5(x+3)+4xleq3(4x-2)

$$5 ( x + 3 ) + 4 x \leq 3 ( 4 x - 2 )$$

Solve for x

$$x\geq 7$$

Solution Steps

Use the distributive property to multiply 5 by x+3.

$$5x+15+4x\leq 3\left(4x-2\right)$$

Combine 5x and 4x to get 9x.

$$9x+15\leq 3\left(4x-2\right)$$

Use the distributive property to multiply 3 by 4x-2.

$$9x+15\leq 12x-6$$

Subtract 12x from both sides.

$$9x+15-12x\leq -6$$

Combine 9x and -12x to get -3x.

$$-3x+15\leq -6$$

Subtract 15 from both sides.

$$-3x\leq -6-15$$

Subtract 15 from -6 to get -21.

$$-3x\leq -21$$

Divide both sides by -3. Since -3 is negative, the inequality direction is changed.

$$x\geq \frac{-21}{-3}$$

Divide -21 by -3 to get 7.

$$x\geq 7$$