Solve 5(4-5)^2+3(5-1)-2(1+2)^2(2)+2(3)(4)

$$5 ( 4 - 5 ) ^ { 2 } + 3 ( 5 - 1 ) - 2 ( 1 + 2 ) ^ { 2 } ( 2 ) + 2 ( 3 ) ( 4 )$$

Evaluate

$$5$$

Solution Steps

Subtract 5 from 4 to get -1.

$$5\left(-1\right)^{2}+3\left(5-1\right)-2\left(1+2\right)^{2}\times 2+2\times 3\times 4$$

Calculate -1 to the power of 2 and get 1.

$$5\times 1+3\left(5-1\right)-2\left(1+2\right)^{2}\times 2+2\times 3\times 4$$

Multiply 5 and 1 to get 5.

$$5+3\left(5-1\right)-2\left(1+2\right)^{2}\times 2+2\times 3\times 4$$

Subtract 1 from 5 to get 4.

$$5+3\times 4-2\left(1+2\right)^{2}\times 2+2\times 3\times 4$$

Multiply 3 and 4 to get 12.

$$5+12-2\left(1+2\right)^{2}\times 2+2\times 3\times 4$$

Add 5 and 12 to get 17.

$$17-2\left(1+2\right)^{2}\times 2+2\times 3\times 4$$

Add 1 and 2 to get 3.

$$17-2\times 3^{2}\times 2+2\times 3\times 4$$

Calculate 3 to the power of 2 and get 9.

$$17-2\times 9\times 2+2\times 3\times 4$$

Multiply 2 and 9 to get 18.

$$17-18\times 2+2\times 3\times 4$$

Multiply 18 and 2 to get 36.

$$17-36+2\times 3\times 4$$

Subtract 36 from 17 to get -19.

$$-19+2\times 3\times 4$$

Multiply 2 and 3 to get 6.

$$-19+6\times 4$$

Multiply 6 and 4 to get 24.

$$-19+24$$

Add -19 and 24 to get 5.

$$5$$

Factor

$$5$$