Solve 5(3^2-2^3)-sqrt{20-2^2}

$$5 ( 3 ^ { 2 } - 2 ^ { 3 } ) - \sqrt { 20 - 2 ^ { 2 } }$$

Evaluate

$$1$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$5\left(9-2^{3}\right)-\sqrt{20-2^{2}}$$

Calculate 2 to the power of 3 and get 8.

$$5\left(9-8\right)-\sqrt{20-2^{2}}$$

Subtract 8 from 9 to get 1.

$$5\times 1-\sqrt{20-2^{2}}$$

Multiply 5 and 1 to get 5.

$$5-\sqrt{20-2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$5-\sqrt{20-4}$$

Subtract 4 from 20 to get 16.

$$5-\sqrt{16}$$

Calculate the square root of 16 and get 4.

$$5-4$$

Subtract 4 from 5 to get 1.

$$1$$

Factor

$$1$$