Solve 5(1+x)^2=5.832

$$5 ( 1 + x ) ^ { 2 } = 5.832$$

Solve for x

$$x=0.08$$

$$x=-2.08$$

Steps by Finding Square Root

Divide both sides by 5.

$$\frac{5\left(x+1\right)^{2}}{5}=\frac{5.832}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$\left(x+1\right)^{2}=\frac{5.832}{5}$$

Divide 5.832 by 5.

$$\left(x+1\right)^{2}=1.1664$$

Take the square root of both sides of the equation.

$$x+1=\frac{27}{25} x+1=-\frac{27}{25}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{27}{25}-1 x+1-1=-\frac{27}{25}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{27}{25}-1 x=-\frac{27}{25}-1$$

Subtract 1 from \frac{27}{25}.

$$x=\frac{2}{25}$$

Subtract 1 from -\frac{27}{25}.

$$x=-\frac{52}{25}$$

The equation is now solved.

$$x=\frac{2}{25} x=-\frac{52}{25}$$