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5x^{2}=100
Add 100 to both sides. Anything plus zero gives itself.
x^{2}=\frac{100}{5}
Divide both sides by 5.
x^{2}=20
Divide 100 by 5 to get 20.
x=2\sqrt{5} x=-2\sqrt{5}
Take the square root of both sides of the equation.
5x^{2}-100=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 5\left(-100\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and -100 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 5\left(-100\right)}}{2\times 5}
Square 0.
x=\frac{0±\sqrt{-20\left(-100\right)}}{2\times 5}
Multiply -4 times 5.
x=\frac{0±\sqrt{2000}}{2\times 5}
Multiply -20 times -100.
x=\frac{0±20\sqrt{5}}{2\times 5}
Take the square root of 2000.
x=\frac{0±20\sqrt{5}}{10}
Multiply 2 times 5.
x=2\sqrt{5}
Now solve the equation x=\frac{0±20\sqrt{5}}{10} when ± is plus.
x=-2\sqrt{5}
Now solve the equation x=\frac{0±20\sqrt{5}}{10} when ± is minus.
x=2\sqrt{5} x=-2\sqrt{5}
The equation is now solved.