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5x^{2}-48=0
Subtract 55 from 7 to get -48.
5x^{2}=48
Add 48 to both sides. Anything plus zero gives itself.
x^{2}=\frac{48}{5}
Divide both sides by 5.
x=\frac{4\sqrt{15}}{5} x=-\frac{4\sqrt{15}}{5}
Take the square root of both sides of the equation.
5x^{2}-48=0
Subtract 55 from 7 to get -48.
x=\frac{0±\sqrt{0^{2}-4\times 5\left(-48\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and -48 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 5\left(-48\right)}}{2\times 5}
Square 0.
x=\frac{0±\sqrt{-20\left(-48\right)}}{2\times 5}
Multiply -4 times 5.
x=\frac{0±\sqrt{960}}{2\times 5}
Multiply -20 times -48.
x=\frac{0±8\sqrt{15}}{2\times 5}
Take the square root of 960.
x=\frac{0±8\sqrt{15}}{10}
Multiply 2 times 5.
x=\frac{4\sqrt{15}}{5}
Now solve the equation x=\frac{0±8\sqrt{15}}{10} when ± is plus.
x=-\frac{4\sqrt{15}}{5}
Now solve the equation x=\frac{0±8\sqrt{15}}{10} when ± is minus.
x=\frac{4\sqrt{15}}{5} x=-\frac{4\sqrt{15}}{5}
The equation is now solved.