Skip to main content
Solve for x
Tick mark Image
Graph

Similar Problems from Web Search

Share

x\left(5x+6+1\right)=0
Factor out x.
x=0 x=-\frac{7}{5}
To find equation solutions, solve x=0 and 5x+7=0.
5x^{2}+7x=0
Combine 6x and x to get 7x.
x=\frac{-7±\sqrt{7^{2}}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 7 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-7±7}{2\times 5}
Take the square root of 7^{2}.
x=\frac{-7±7}{10}
Multiply 2 times 5.
x=\frac{0}{10}
Now solve the equation x=\frac{-7±7}{10} when ± is plus. Add -7 to 7.
x=0
Divide 0 by 10.
x=-\frac{14}{10}
Now solve the equation x=\frac{-7±7}{10} when ± is minus. Subtract 7 from -7.
x=-\frac{7}{5}
Reduce the fraction \frac{-14}{10} to lowest terms by extracting and canceling out 2.
x=0 x=-\frac{7}{5}
The equation is now solved.
5x^{2}+7x=0
Combine 6x and x to get 7x.
\frac{5x^{2}+7x}{5}=\frac{0}{5}
Divide both sides by 5.
x^{2}+\frac{7}{5}x=\frac{0}{5}
Dividing by 5 undoes the multiplication by 5.
x^{2}+\frac{7}{5}x=0
Divide 0 by 5.
x^{2}+\frac{7}{5}x+\left(\frac{7}{10}\right)^{2}=\left(\frac{7}{10}\right)^{2}
Divide \frac{7}{5}, the coefficient of the x term, by 2 to get \frac{7}{10}. Then add the square of \frac{7}{10} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+\frac{7}{5}x+\frac{49}{100}=\frac{49}{100}
Square \frac{7}{10} by squaring both the numerator and the denominator of the fraction.
\left(x+\frac{7}{10}\right)^{2}=\frac{49}{100}
Factor x^{2}+\frac{7}{5}x+\frac{49}{100}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{7}{10}\right)^{2}}=\sqrt{\frac{49}{100}}
Take the square root of both sides of the equation.
x+\frac{7}{10}=\frac{7}{10} x+\frac{7}{10}=-\frac{7}{10}
Simplify.
x=0 x=-\frac{7}{5}
Subtract \frac{7}{10} from both sides of the equation.