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Solve for x (complex solution)
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5x^{2}+50x+100=2500000
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
5x^{2}+50x+100-2500000=2500000-2500000
Subtract 2500000 from both sides of the equation.
5x^{2}+50x+100-2500000=0
Subtracting 2500000 from itself leaves 0.
5x^{2}+50x-2499900=0
Subtract 2500000 from 100.
x=\frac{-50±\sqrt{50^{2}-4\times 5\left(-2499900\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 50 for b, and -2499900 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-50±\sqrt{2500-4\times 5\left(-2499900\right)}}{2\times 5}
Square 50.
x=\frac{-50±\sqrt{2500-20\left(-2499900\right)}}{2\times 5}
Multiply -4 times 5.
x=\frac{-50±\sqrt{2500+49998000}}{2\times 5}
Multiply -20 times -2499900.
x=\frac{-50±\sqrt{50000500}}{2\times 5}
Add 2500 to 49998000.
x=\frac{-50±10\sqrt{500005}}{2\times 5}
Take the square root of 50000500.
x=\frac{-50±10\sqrt{500005}}{10}
Multiply 2 times 5.
x=\frac{10\sqrt{500005}-50}{10}
Now solve the equation x=\frac{-50±10\sqrt{500005}}{10} when ± is plus. Add -50 to 10\sqrt{500005}.
x=\sqrt{500005}-5
Divide -50+10\sqrt{500005} by 10.
x=\frac{-10\sqrt{500005}-50}{10}
Now solve the equation x=\frac{-50±10\sqrt{500005}}{10} when ± is minus. Subtract 10\sqrt{500005} from -50.
x=-\sqrt{500005}-5
Divide -50-10\sqrt{500005} by 10.
x=\sqrt{500005}-5 x=-\sqrt{500005}-5
The equation is now solved.
5x^{2}+50x+100=2500000
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
5x^{2}+50x+100-100=2500000-100
Subtract 100 from both sides of the equation.
5x^{2}+50x=2500000-100
Subtracting 100 from itself leaves 0.
5x^{2}+50x=2499900
Subtract 100 from 2500000.
\frac{5x^{2}+50x}{5}=\frac{2499900}{5}
Divide both sides by 5.
x^{2}+\frac{50}{5}x=\frac{2499900}{5}
Dividing by 5 undoes the multiplication by 5.
x^{2}+10x=\frac{2499900}{5}
Divide 50 by 5.
x^{2}+10x=499980
Divide 2499900 by 5.
x^{2}+10x+5^{2}=499980+5^{2}
Divide 10, the coefficient of the x term, by 2 to get 5. Then add the square of 5 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+10x+25=499980+25
Square 5.
x^{2}+10x+25=500005
Add 499980 to 25.
\left(x+5\right)^{2}=500005
Factor x^{2}+10x+25. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+5\right)^{2}}=\sqrt{500005}
Take the square root of both sides of the equation.
x+5=\sqrt{500005} x+5=-\sqrt{500005}
Simplify.
x=\sqrt{500005}-5 x=-\sqrt{500005}-5
Subtract 5 from both sides of the equation.
5x^{2}+50x+100=2500000
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
5x^{2}+50x+100-2500000=2500000-2500000
Subtract 2500000 from both sides of the equation.
5x^{2}+50x+100-2500000=0
Subtracting 2500000 from itself leaves 0.
5x^{2}+50x-2499900=0
Subtract 2500000 from 100.
x=\frac{-50±\sqrt{50^{2}-4\times 5\left(-2499900\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 50 for b, and -2499900 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-50±\sqrt{2500-4\times 5\left(-2499900\right)}}{2\times 5}
Square 50.
x=\frac{-50±\sqrt{2500-20\left(-2499900\right)}}{2\times 5}
Multiply -4 times 5.
x=\frac{-50±\sqrt{2500+49998000}}{2\times 5}
Multiply -20 times -2499900.
x=\frac{-50±\sqrt{50000500}}{2\times 5}
Add 2500 to 49998000.
x=\frac{-50±10\sqrt{500005}}{2\times 5}
Take the square root of 50000500.
x=\frac{-50±10\sqrt{500005}}{10}
Multiply 2 times 5.
x=\frac{10\sqrt{500005}-50}{10}
Now solve the equation x=\frac{-50±10\sqrt{500005}}{10} when ± is plus. Add -50 to 10\sqrt{500005}.
x=\sqrt{500005}-5
Divide -50+10\sqrt{500005} by 10.
x=\frac{-10\sqrt{500005}-50}{10}
Now solve the equation x=\frac{-50±10\sqrt{500005}}{10} when ± is minus. Subtract 10\sqrt{500005} from -50.
x=-\sqrt{500005}-5
Divide -50-10\sqrt{500005} by 10.
x=\sqrt{500005}-5 x=-\sqrt{500005}-5
The equation is now solved.
5x^{2}+50x+100=2500000
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
5x^{2}+50x+100-100=2500000-100
Subtract 100 from both sides of the equation.
5x^{2}+50x=2500000-100
Subtracting 100 from itself leaves 0.
5x^{2}+50x=2499900
Subtract 100 from 2500000.
\frac{5x^{2}+50x}{5}=\frac{2499900}{5}
Divide both sides by 5.
x^{2}+\frac{50}{5}x=\frac{2499900}{5}
Dividing by 5 undoes the multiplication by 5.
x^{2}+10x=\frac{2499900}{5}
Divide 50 by 5.
x^{2}+10x=499980
Divide 2499900 by 5.
x^{2}+10x+5^{2}=499980+5^{2}
Divide 10, the coefficient of the x term, by 2 to get 5. Then add the square of 5 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+10x+25=499980+25
Square 5.
x^{2}+10x+25=500005
Add 499980 to 25.
\left(x+5\right)^{2}=500005
Factor x^{2}+10x+25. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+5\right)^{2}}=\sqrt{500005}
Take the square root of both sides of the equation.
x+5=\sqrt{500005} x+5=-\sqrt{500005}
Simplify.
x=\sqrt{500005}-5 x=-\sqrt{500005}-5
Subtract 5 from both sides of the equation.