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Solve for x (complex solution)
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5x^{2}=-2
Subtract 2 from both sides. Anything subtracted from zero gives its negation.
x^{2}=-\frac{2}{5}
Divide both sides by 5.
x=\frac{\sqrt{10}i}{5} x=-\frac{\sqrt{10}i}{5}
The equation is now solved.
5x^{2}+2=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 5\times 2}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and 2 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 5\times 2}}{2\times 5}
Square 0.
x=\frac{0±\sqrt{-20\times 2}}{2\times 5}
Multiply -4 times 5.
x=\frac{0±\sqrt{-40}}{2\times 5}
Multiply -20 times 2.
x=\frac{0±2\sqrt{10}i}{2\times 5}
Take the square root of -40.
x=\frac{0±2\sqrt{10}i}{10}
Multiply 2 times 5.
x=\frac{\sqrt{10}i}{5}
Now solve the equation x=\frac{0±2\sqrt{10}i}{10} when ± is plus.
x=-\frac{\sqrt{10}i}{5}
Now solve the equation x=\frac{0±2\sqrt{10}i}{10} when ± is minus.
x=\frac{\sqrt{10}i}{5} x=-\frac{\sqrt{10}i}{5}
The equation is now solved.