Solve 510^-1+610^-2+4*10^-4

$$5 { 10 }^{ -1 } +6 { 10 }^{ -2 } +4 \cdot { 10 }^{ -4 }$$

Evaluate

$$\frac{1401}{2500}=0.5604$$

Solution Steps

Calculate 10 to the power of -1 and get \frac{1}{10}.

$$5\times \frac{1}{10}+6\times 10^{-2}+4\times 10^{-4}$$

Multiply 5 and \frac{1}{10} to get \frac{1}{2}.

$$\frac{1}{2}+6\times 10^{-2}+4\times 10^{-4}$$

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$\frac{1}{2}+6\times \frac{1}{100}+4\times 10^{-4}$$

Multiply 6 and \frac{1}{100} to get \frac{3}{50}.

$$\frac{1}{2}+\frac{3}{50}+4\times 10^{-4}$$

Add \frac{1}{2} and \frac{3}{50} to get \frac{14}{25}.

$$\frac{14}{25}+4\times 10^{-4}$$

Calculate 10 to the power of -4 and get \frac{1}{10000}.

$$\frac{14}{25}+4\times \frac{1}{10000}$$

Multiply 4 and \frac{1}{10000} to get \frac{1}{2500}.

$$\frac{14}{25}+\frac{1}{2500}$$

Add \frac{14}{25} and \frac{1}{2500} to get \frac{1401}{2500}.

$$\frac{1401}{2500}$$

Factor

$$\frac{3 \cdot 467}{2 ^ {2} \cdot 5 ^ {4}} = 0.5604$$