Solve 5*20+(x-5)*4=(5*20+44)*09

$$5 \times 20 + ( x - 5 ) \times 4 = ( 5 \times 20 + 44 ) \times 09$$

Solve for x

$$x=-20$$

Steps for Solving Linear Equation

Multiply 5 and 20 to get 100.

$$100+\left(x-5\right)\times 4=\left(5\times 20+44\right)\times 0\times 9$$

Use the distributive property to multiply x-5 by 4.

$$100+4x-20=\left(5\times 20+44\right)\times 0\times 9$$

Subtract 20 from 100 to get 80.

$$80+4x=\left(5\times 20+44\right)\times 0\times 9$$

Multiply 5 and 20 to get 100.

$$80+4x=\left(100+44\right)\times 0\times 9$$

Add 100 and 44 to get 144.

$$80+4x=144\times 0\times 9$$

Multiply 144 and 0 to get 0.

$$80+4x=0\times 9$$

Multiply 0 and 9 to get 0.

$$80+4x=0$$

Subtract 80 from both sides. Anything subtracted from zero gives its negation.

$$4x=-80$$

Divide both sides by 4.

$$x=\frac{-80}{4}$$

Divide -80 by 4 to get -20.

$$x=-20$$