Solve 5*(11/3-3/5)+2.5div(2.5-1)

$$5 \times ( 1 \frac { 1 } { 3 } - \frac { 3 } { 5 } ) + 2.5 \div ( 2.5 - 1 )$$

Evaluate

$$\frac{16}{3}\approx 5.333333333$$

Solution Steps

Multiply 1 and 3 to get 3.

$$5\left(\frac{3+1}{3}-\frac{3}{5}\right)+\frac{2.5}{2.5-1}$$

Add 3 and 1 to get 4.

$$5\left(\frac{4}{3}-\frac{3}{5}\right)+\frac{2.5}{2.5-1}$$

Least common multiple of 3 and 5 is 15. Convert \frac{4}{3} and \frac{3}{5} to fractions with denominator 15.

$$5\left(\frac{20}{15}-\frac{9}{15}\right)+\frac{2.5}{2.5-1}$$

Since \frac{20}{15} and \frac{9}{15} have the same denominator, subtract them by subtracting their numerators.

$$5\times \frac{20-9}{15}+\frac{2.5}{2.5-1}$$

Subtract 9 from 20 to get 11.

$$5\times \frac{11}{15}+\frac{2.5}{2.5-1}$$

Express 5\times \frac{11}{15} as a single fraction.

$$\frac{5\times 11}{15}+\frac{2.5}{2.5-1}$$

Multiply 5 and 11 to get 55.

$$\frac{55}{15}+\frac{2.5}{2.5-1}$$

Reduce the fraction \frac{55}{15} to lowest terms by extracting and canceling out 5.

$$\frac{11}{3}+\frac{2.5}{2.5-1}$$

Subtract 1 from 2.5 to get 1.5.

$$\frac{11}{3}+\frac{2.5}{1.5}$$

Expand \frac{2.5}{1.5} by multiplying both numerator and the denominator by 10.

$$\frac{11}{3}+\frac{25}{15}$$

Reduce the fraction \frac{25}{15} to lowest terms by extracting and canceling out 5.

$$\frac{11}{3}+\frac{5}{3}$$

Since \frac{11}{3} and \frac{5}{3} have the same denominator, add them by adding their numerators.

$$\frac{11+5}{3}$$

Add 11 and 5 to get 16.

$$\frac{16}{3}$$

Factor

$$\frac{2 ^ {4}}{3} = 5\frac{1}{3} = 5.333333333333333$$