Solve 5*3-7div9*2+3div8*6-2=

$$5 \times 3-7 \div 9 \times 2+3 \div 8 \times 6-2=$$

Evaluate

$$\frac{493}{36}\approx 13.694444444$$

Solution Steps

Multiply 5 and 3 to get 15.

$$15-\frac{7}{9}\times 2+\frac{3}{8}\times 6-2$$

Express \frac{7}{9}\times 2 as a single fraction.

$$15-\frac{7\times 2}{9}+\frac{3}{8}\times 6-2$$

Multiply 7 and 2 to get 14.

$$15-\frac{14}{9}+\frac{3}{8}\times 6-2$$

Convert 15 to fraction \frac{135}{9}.

$$\frac{135}{9}-\frac{14}{9}+\frac{3}{8}\times 6-2$$

Since \frac{135}{9} and \frac{14}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{135-14}{9}+\frac{3}{8}\times 6-2$$

Subtract 14 from 135 to get 121.

$$\frac{121}{9}+\frac{3}{8}\times 6-2$$

Express \frac{3}{8}\times 6 as a single fraction.

$$\frac{121}{9}+\frac{3\times 6}{8}-2$$

Multiply 3 and 6 to get 18.

$$\frac{121}{9}+\frac{18}{8}-2$$

Reduce the fraction \frac{18}{8} to lowest terms by extracting and canceling out 2.

$$\frac{121}{9}+\frac{9}{4}-2$$

Least common multiple of 9 and 4 is 36. Convert \frac{121}{9} and \frac{9}{4} to fractions with denominator 36.

$$\frac{484}{36}+\frac{81}{36}-2$$

Since \frac{484}{36} and \frac{81}{36} have the same denominator, add them by adding their numerators.

$$\frac{484+81}{36}-2$$

Add 484 and 81 to get 565.

$$\frac{565}{36}-2$$

Convert 2 to fraction \frac{72}{36}.

$$\frac{565}{36}-\frac{72}{36}$$

Since \frac{565}{36} and \frac{72}{36} have the same denominator, subtract them by subtracting their numerators.

$$\frac{565-72}{36}$$

Subtract 72 from 565 to get 493.

$$\frac{493}{36}$$

Factor

$$\frac{17 \cdot 29}{2 ^ {2} \cdot 3 ^ {2}} = 13\frac{25}{36} = 13.694444444444445$$