Solve 5*(x-3)+4*(x+5)=20(x-8)

$$5 \times (x-3)+4 \times (x+5)=20(x-8)$$

Solve for x

$$x=15$$

Steps for Solving Linear Equation

Use the distributive property to multiply 5 by x-3.

$$5x-15+4\left(x+5\right)=20\left(x-8\right)$$

Use the distributive property to multiply 4 by x+5.

$$5x-15+4x+20=20\left(x-8\right)$$

Combine 5x and 4x to get 9x.

$$9x-15+20=20\left(x-8\right)$$

Add -15 and 20 to get 5.

$$9x+5=20\left(x-8\right)$$

Use the distributive property to multiply 20 by x-8.

$$9x+5=20x-160$$

Subtract 20x from both sides.

$$9x+5-20x=-160$$

Combine 9x and -20x to get -11x.

$$-11x+5=-160$$

Subtract 5 from both sides.

$$-11x=-160-5$$

Subtract 5 from -160 to get -165.

$$-11x=-165$$

Divide both sides by -11.

$$x=\frac{-165}{-11}$$

Divide -165 by -11 to get 15.

$$x=15$$