Solve 5*2^2-18*2-4-5

$$5 \times { 2 }^{ 2 } -18 \cdot 2-4-5$$

Evaluate

$$-25$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$5\times 4-18\times 2-4-5$$

Multiply 5 and 4 to get 20.

$$20-18\times 2-4-5$$

Multiply 18 and 2 to get 36.

$$20-36-4-5$$

Subtract 36 from 20 to get -16.

$$-16-4-5$$

Subtract 4 from -16 to get -20.

$$-20-5$$

Subtract 5 from -20 to get -25.

$$-25$$

Factor

$$-25$$