Solve 5*06^2+22*06-15=0

$$5 \times { 06 }^{ 2 } +22 \cdot 06-15 = 0$$

Verify

Solution Steps

Multiply 0 and 6 to get 0.

$$5\times 0^{2}+22\times 0\times 6-15=0$$

Calculate 0 to the power of 2 and get 0.

$$5\times 0+22\times 0\times 6-15=0$$

Multiply 5 and 0 to get 0.

$$0+22\times 0\times 6-15=0$$

Multiply 22 and 0 to get 0.

$$0+0\times 6-15=0$$

Multiply 0 and 6 to get 0.

$$0+0-15=0$$

Add 0 and 0 to get 0.

$$-15=0$$

Compare -15 and 0.

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