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5\sqrt{2}-2\times 6\sqrt{3}-7\sqrt{3}+9\sqrt{2}
Factor 108=6^{2}\times 3. Rewrite the square root of the product \sqrt{6^{2}\times 3} as the product of square roots \sqrt{6^{2}}\sqrt{3}. Take the square root of 6^{2}.
5\sqrt{2}-12\sqrt{3}-7\sqrt{3}+9\sqrt{2}
Multiply -2 and 6 to get -12.
5\sqrt{2}-19\sqrt{3}+9\sqrt{2}
Combine -12\sqrt{3} and -7\sqrt{3} to get -19\sqrt{3}.
14\sqrt{2}-19\sqrt{3}
Combine 5\sqrt{2} and 9\sqrt{2} to get 14\sqrt{2}.