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5\sqrt{2}+4\sqrt{3}-\sqrt{98}
Multiply 2 and 2 to get 4.
5\sqrt{2}+4\sqrt{3}-7\sqrt{2}
Factor 98=7^{2}\times 2. Rewrite the square root of the product \sqrt{7^{2}\times 2} as the product of square roots \sqrt{7^{2}}\sqrt{2}. Take the square root of 7^{2}.
-2\sqrt{2}+4\sqrt{3}
Combine 5\sqrt{2} and -7\sqrt{2} to get -2\sqrt{2}.