Solve 5sin(90^circ)-4/5tan(180^circ)-2/3sin(270^circ)+1=

$$5 \sin ( 90 ^ { \circ } ) - \frac{ 4 }{ 5 } \tan ( 180 ^ { \circ } ) - \frac{ 2 }{ 3 } \sin ( 270 ^ { \circ } ) +1=$$

Evaluate

$$\frac{20}{3}\approx 6.666666667$$

Solution Steps

Get the value of \sin(90) from trigonometric values table.

$$5\times 1-\frac{4}{5}\tan(180)-\frac{2}{3}\sin(270)+1$$

Multiply 5 and 1 to get 5.

$$5-\frac{4}{5}\tan(180)-\frac{2}{3}\sin(270)+1$$

Get the value of \tan(180) from trigonometric values table.

$$5-\frac{4}{5}\times 0-\frac{2}{3}\sin(270)+1$$

Multiply \frac{4}{5} and 0 to get 0.

$$5-0-\frac{2}{3}\sin(270)+1$$

Subtract 0 from 5 to get 5.

$$5-\frac{2}{3}\sin(270)+1$$

Get the value of \sin(270) from trigonometric values table.

$$5-\frac{2}{3}\left(-1\right)+1$$

Multiply \frac{2}{3} and -1 to get -\frac{2}{3}.

$$5-\left(-\frac{2}{3}\right)+1$$

The opposite of -\frac{2}{3} is \frac{2}{3}.

$$5+\frac{2}{3}+1$$

Add 5 and \frac{2}{3} to get \frac{17}{3}.

$$\frac{17}{3}+1$$

Add \frac{17}{3} and 1 to get \frac{20}{3}.

$$\frac{20}{3}$$