Solve 5lfloor2(-3-2)rfloor=27*+4

$$5 \lfloor 2(-3-2) \rfloor =27 \times +4$$

Verify

Solution Steps

Subtract 2 from -3 to get -5.

$$5\lfloor 2\left(-5\right)\rfloor =27\times 4$$

Multiply 2 and -5 to get -10.

$$5\lfloor -10\rfloor =27\times 4$$

The floor of a real number a is the largest integer number less than or equal to a. The floor of -10 is -10.

$$5\left(-10\right)=27\times 4$$

Multiply 5 and -10 to get -50.

$$-50=27\times 4$$

Multiply 27 and 4 to get 108.

$$-50=108$$

Compare -50 and 108.

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