Solve 5left(t+2right)-3left(-4t-4right)+4left(-2t+3right)-7=0

$$5 \left( t+2 \right) -3 \left( -4t-4 \right) +4 \left( -2t+3 \right) -7=0$$

Solve for t

$$t=-3$$

Steps for Solving Linear Equation

Use the distributive property to multiply 5 by t+2.

$$5t+10-3\left(-4t-4\right)+4\left(-2t+3\right)-7=0$$

Use the distributive property to multiply -3 by -4t-4.

$$5t+10+12t+12+4\left(-2t+3\right)-7=0$$

Combine 5t and 12t to get 17t.

$$17t+10+12+4\left(-2t+3\right)-7=0$$

Add 10 and 12 to get 22.

$$17t+22+4\left(-2t+3\right)-7=0$$

Use the distributive property to multiply 4 by -2t+3.

$$17t+22-8t+12-7=0$$

Combine 17t and -8t to get 9t.

$$9t+22+12-7=0$$

Add 22 and 12 to get 34.

$$9t+34-7=0$$

Subtract 7 from 34 to get 27.

$$9t+27=0$$

Subtract 27 from both sides. Anything subtracted from zero gives its negation.

$$9t=-27$$

Divide both sides by 9.

$$t=\frac{-27}{9}$$

Divide -27 by 9 to get -3.

$$t=-3$$