Solve 54/3+41/6

$$5 \frac { 4 } { 3 } + 4 \frac { 1 } { 6 }$$

Evaluate

$$\frac{21}{2}=10.5$$

Solution Steps

Multiply 5 and 3 to get 15.

$$\frac{15+4}{3}+\frac{4\times 6+1}{6}$$

Add 15 and 4 to get 19.

$$\frac{19}{3}+\frac{4\times 6+1}{6}$$

Multiply 4 and 6 to get 24.

$$\frac{19}{3}+\frac{24+1}{6}$$

Add 24 and 1 to get 25.

$$\frac{19}{3}+\frac{25}{6}$$

Least common multiple of 3 and 6 is 6. Convert \frac{19}{3} and \frac{25}{6} to fractions with denominator 6.

$$\frac{38}{6}+\frac{25}{6}$$

Since \frac{38}{6} and \frac{25}{6} have the same denominator, add them by adding their numerators.

$$\frac{38+25}{6}$$

Add 38 and 25 to get 63.

$$\frac{63}{6}$$

Reduce the fraction \frac{63}{6} to lowest terms by extracting and canceling out 3.

$$\frac{21}{2}$$

Factor

$$\frac{3 \cdot 7}{2} = 10\frac{1}{2} = 10.5$$