Solve 54/19*34/7+115/19:7/25-1frac{2}{3}

$$5 \frac { 4 } { 19 } \cdot 3 \frac { 4 } { 7 } + 1 \frac { 15 } { 19 } : \frac { 7 } { 25 } - 1 \frac { 2 } { 3 }$$

Evaluate

$$\frac{70}{3}\approx 23.333333333$$

Solution Steps

Multiply 5 and 19 to get 95.

$$\frac{95+4}{19}\times \frac{3\times 7+4}{7}+\frac{\frac{1\times 19+15}{19}}{\frac{7}{25}}-\frac{1\times 3+2}{3}$$

Add 95 and 4 to get 99.

$$\frac{99}{19}\times \frac{3\times 7+4}{7}+\frac{\frac{1\times 19+15}{19}}{\frac{7}{25}}-\frac{1\times 3+2}{3}$$

Multiply 3 and 7 to get 21.

$$\frac{99}{19}\times \frac{21+4}{7}+\frac{\frac{1\times 19+15}{19}}{\frac{7}{25}}-\frac{1\times 3+2}{3}$$

Add 21 and 4 to get 25.

$$\frac{99}{19}\times \frac{25}{7}+\frac{\frac{1\times 19+15}{19}}{\frac{7}{25}}-\frac{1\times 3+2}{3}$$

Multiply \frac{99}{19} times \frac{25}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{99\times 25}{19\times 7}+\frac{\frac{1\times 19+15}{19}}{\frac{7}{25}}-\frac{1\times 3+2}{3}$$

Do the multiplications in the fraction \frac{99\times 25}{19\times 7}.

$$\frac{2475}{133}+\frac{\frac{1\times 19+15}{19}}{\frac{7}{25}}-\frac{1\times 3+2}{3}$$

Divide \frac{1\times 19+15}{19} by \frac{7}{25} by multiplying \frac{1\times 19+15}{19} by the reciprocal of \frac{7}{25}.

$$\frac{2475}{133}+\frac{\left(1\times 19+15\right)\times 25}{19\times 7}-\frac{1\times 3+2}{3}$$

Multiply 1 and 19 to get 19.

$$\frac{2475}{133}+\frac{\left(19+15\right)\times 25}{19\times 7}-\frac{1\times 3+2}{3}$$

Add 19 and 15 to get 34.

$$\frac{2475}{133}+\frac{34\times 25}{19\times 7}-\frac{1\times 3+2}{3}$$

Multiply 34 and 25 to get 850.

$$\frac{2475}{133}+\frac{850}{19\times 7}-\frac{1\times 3+2}{3}$$

Multiply 19 and 7 to get 133.

$$\frac{2475}{133}+\frac{850}{133}-\frac{1\times 3+2}{3}$$

Since \frac{2475}{133} and \frac{850}{133} have the same denominator, add them by adding their numerators.

$$\frac{2475+850}{133}-\frac{1\times 3+2}{3}$$

Add 2475 and 850 to get 3325.

$$\frac{3325}{133}-\frac{1\times 3+2}{3}$$

Divide 3325 by 133 to get 25.

$$25-\frac{1\times 3+2}{3}$$

Multiply 1 and 3 to get 3.

$$25-\frac{3+2}{3}$$

Add 3 and 2 to get 5.

$$25-\frac{5}{3}$$

Convert 25 to fraction \frac{75}{3}.

$$\frac{75}{3}-\frac{5}{3}$$

Since \frac{75}{3} and \frac{5}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{75-5}{3}$$

Subtract 5 from 75 to get 70.

$$\frac{70}{3}$$

Factor

$$\frac{2 \cdot 5 \cdot 7}{3} = 23\frac{1}{3} = 23.333333333333332$$