Solve 53/10+91/5=

$$5 \frac { 3 } { 10 } + 9 \frac { 1 } { 5 } =$$

Evaluate

$$\frac{29}{2}=14.5$$

Solution Steps

Multiply 5 and 10 to get 50.

$$\frac{50+3}{10}+\frac{9\times 5+1}{5}$$

Add 50 and 3 to get 53.

$$\frac{53}{10}+\frac{9\times 5+1}{5}$$

Multiply 9 and 5 to get 45.

$$\frac{53}{10}+\frac{45+1}{5}$$

Add 45 and 1 to get 46.

$$\frac{53}{10}+\frac{46}{5}$$

Least common multiple of 10 and 5 is 10. Convert \frac{53}{10} and \frac{46}{5} to fractions with denominator 10.

$$\frac{53}{10}+\frac{92}{10}$$

Since \frac{53}{10} and \frac{92}{10} have the same denominator, add them by adding their numerators.

$$\frac{53+92}{10}$$

Add 53 and 92 to get 145.

$$\frac{145}{10}$$

Reduce the fraction \frac{145}{10} to lowest terms by extracting and canceling out 5.

$$\frac{29}{2}$$

Factor

$$\frac{29}{2} = 14\frac{1}{2} = 14.5$$