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\frac{\left(5\times 7+1\right)\times 4}{7\left(2\times 4+1\right)}
Divide \frac{5\times 7+1}{7} by \frac{2\times 4+1}{4} by multiplying \frac{5\times 7+1}{7} by the reciprocal of \frac{2\times 4+1}{4}.
\frac{\left(35+1\right)\times 4}{7\left(2\times 4+1\right)}
Multiply 5 and 7 to get 35.
\frac{36\times 4}{7\left(2\times 4+1\right)}
Add 35 and 1 to get 36.
\frac{144}{7\left(2\times 4+1\right)}
Multiply 36 and 4 to get 144.
\frac{144}{7\left(8+1\right)}
Multiply 2 and 4 to get 8.
\frac{144}{7\times 9}
Add 8 and 1 to get 9.
\frac{144}{63}
Multiply 7 and 9 to get 63.
\frac{16}{7}
Reduce the fraction \frac{144}{63} to lowest terms by extracting and canceling out 9.