Solve 51/7+1/6

$$5 \frac { 1 } { 7 } + \frac { 1 } { 6 }$$

Evaluate

$$\frac{223}{42}\approx 5.30952381$$

Solution Steps

Multiply 5 and 7 to get 35.

$$\frac{35+1}{7}+\frac{1}{6}$$

Add 35 and 1 to get 36.

$$\frac{36}{7}+\frac{1}{6}$$

Least common multiple of 7 and 6 is 42. Convert \frac{36}{7} and \frac{1}{6} to fractions with denominator 42.

$$\frac{216}{42}+\frac{7}{42}$$

Since \frac{216}{42} and \frac{7}{42} have the same denominator, add them by adding their numerators.

$$\frac{216+7}{42}$$

Add 216 and 7 to get 223.

$$\frac{223}{42}$$

Factor

$$\frac{223}{2 \cdot 3 \cdot 7} = 5\frac{13}{42} = 5.309523809523809$$