Solve 51/4-22/3*13/4

$$5 \frac { 1 } { 4 } - 2 \frac { 2 } { 3 } \times 1 \frac { 3 } { 4 }$$

Evaluate

$$\frac{7}{12}\approx 0.583333333$$

Solution Steps

Multiply 5 and 4 to get 20.

$$\frac{20+1}{4}-\frac{2\times 3+2}{3}\times \frac{1\times 4+3}{4}$$

Add 20 and 1 to get 21.

$$\frac{21}{4}-\frac{2\times 3+2}{3}\times \frac{1\times 4+3}{4}$$

Multiply 2 and 3 to get 6.

$$\frac{21}{4}-\frac{6+2}{3}\times \frac{1\times 4+3}{4}$$

Add 6 and 2 to get 8.

$$\frac{21}{4}-\frac{8}{3}\times \frac{1\times 4+3}{4}$$

Multiply 1 and 4 to get 4.

$$\frac{21}{4}-\frac{8}{3}\times \frac{4+3}{4}$$

Add 4 and 3 to get 7.

$$\frac{21}{4}-\frac{8}{3}\times \frac{7}{4}$$

Multiply \frac{8}{3} times \frac{7}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{21}{4}-\frac{8\times 7}{3\times 4}$$

Do the multiplications in the fraction \frac{8\times 7}{3\times 4}.

$$\frac{21}{4}-\frac{56}{12}$$

Reduce the fraction \frac{56}{12} to lowest terms by extracting and canceling out 4.

$$\frac{21}{4}-\frac{14}{3}$$

Least common multiple of 4 and 3 is 12. Convert \frac{21}{4} and \frac{14}{3} to fractions with denominator 12.

$$\frac{63}{12}-\frac{56}{12}$$

Since \frac{63}{12} and \frac{56}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{63-56}{12}$$

Subtract 56 from 63 to get 7.

$$\frac{7}{12}$$

Factor

$$\frac{7}{2 ^ {2} \cdot 3} = 0.5833333333333334$$