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\frac{\left(5\times 3+1\right)\times 7}{3\left(1\times 7+1\right)}
Divide \frac{5\times 3+1}{3} by \frac{1\times 7+1}{7} by multiplying \frac{5\times 3+1}{3} by the reciprocal of \frac{1\times 7+1}{7}.
\frac{\left(15+1\right)\times 7}{3\left(1\times 7+1\right)}
Multiply 5 and 3 to get 15.
\frac{16\times 7}{3\left(1\times 7+1\right)}
Add 15 and 1 to get 16.
\frac{112}{3\left(1\times 7+1\right)}
Multiply 16 and 7 to get 112.
\frac{112}{3\left(7+1\right)}
Multiply 1 and 7 to get 7.
\frac{112}{3\times 8}
Add 7 and 1 to get 8.
\frac{112}{24}
Multiply 3 and 8 to get 24.
\frac{14}{3}
Reduce the fraction \frac{112}{24} to lowest terms by extracting and canceling out 8.