Solve 5*-3^2*(-2)+4^2+(-2)^3-1-2^2

$$5 \cdot - 3 ^ { 2 } \times ( - 2 ) + 4 ^ { 2 } + ( - 2 ) ^ { 3 } - 1 - 2 ^ { 2 }$$

Evaluate

$$93$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$5\left(-9\right)\left(-2\right)+4^{2}+\left(-2\right)^{3}-1-2^{2}$$

Multiply 5 and -9 to get -45.

$$-45\left(-2\right)+4^{2}+\left(-2\right)^{3}-1-2^{2}$$

Multiply -45 and -2 to get 90.

$$90+4^{2}+\left(-2\right)^{3}-1-2^{2}$$

Calculate 4 to the power of 2 and get 16.

$$90+16+\left(-2\right)^{3}-1-2^{2}$$

Add 90 and 16 to get 106.

$$106+\left(-2\right)^{3}-1-2^{2}$$

Calculate -2 to the power of 3 and get -8.

$$106-8-1-2^{2}$$

Subtract 8 from 106 to get 98.

$$98-1-2^{2}$$

Subtract 1 from 98 to get 97.

$$97-2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$97-4$$

Subtract 4 from 97 to get 93.

$$93$$

Factor

$$3\times 31$$