Solve 5*(9+3)-2div(3-2)+[(8*6)div4]div2+5

$$5 \cdot ( 9 + 3 ) - 2 \div ( 3 - 2 ) + [ ( 8 \times 6 ) \div 4 ] \div 2 + 5$$

Evaluate

$$69$$

Solution Steps

Add 9 and 3 to get 12.

$$5\times 12-\frac{2}{3-2}+\frac{\frac{8\times 6}{4}}{2}+5$$

Multiply 5 and 12 to get 60.

$$60-\frac{2}{3-2}+\frac{\frac{8\times 6}{4}}{2}+5$$

Subtract 2 from 3 to get 1.

$$60-\frac{2}{1}+\frac{\frac{8\times 6}{4}}{2}+5$$

Anything divided by one gives itself.

$$60-2+\frac{\frac{8\times 6}{4}}{2}+5$$

Subtract 2 from 60 to get 58.

$$58+\frac{\frac{8\times 6}{4}}{2}+5$$

Express \frac{\frac{8\times 6}{4}}{2} as a single fraction.

$$58+\frac{8\times 6}{4\times 2}+5$$

Cancel out 2\times 4 in both numerator and denominator.

$$58+6+5$$

Add 58 and 6 to get 64.

$$64+5$$

Add 64 and 5 to get 69.

$$69$$

Factor

$$3\times 23$$