Solve for R (complex solution)
\left\{\begin{matrix}R=-\frac{2\left(6a-55\right)}{5y}\text{, }&y\neq 0\\R\in \mathrm{C}\text{, }&a=\frac{55}{6}\text{ and }y=0\end{matrix}\right.
Solve for R
\left\{\begin{matrix}R=-\frac{2\left(6a-55\right)}{5y}\text{, }&y\neq 0\\R\in \mathrm{R}\text{, }&a=\frac{55}{6}\text{ and }y=0\end{matrix}\right.
Solve for a
a=-\frac{5Ry}{12}+\frac{55}{6}
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-80+5Ry=3\left(10-4a\right)
Use the distributive property to multiply 5 by -16+Ry.
-80+5Ry=30-12a
Use the distributive property to multiply 3 by 10-4a.
5Ry=30-12a+80
Add 80 to both sides.
5Ry=110-12a
Add 30 and 80 to get 110.
5yR=110-12a
The equation is in standard form.
\frac{5yR}{5y}=\frac{110-12a}{5y}
Divide both sides by 5y.
R=\frac{110-12a}{5y}
Dividing by 5y undoes the multiplication by 5y.
R=\frac{2\left(55-6a\right)}{5y}
Divide 110-12a by 5y.
-80+5Ry=3\left(10-4a\right)
Use the distributive property to multiply 5 by -16+Ry.
-80+5Ry=30-12a
Use the distributive property to multiply 3 by 10-4a.
5Ry=30-12a+80
Add 80 to both sides.
5Ry=110-12a
Add 30 and 80 to get 110.
5yR=110-12a
The equation is in standard form.
\frac{5yR}{5y}=\frac{110-12a}{5y}
Divide both sides by 5y.
R=\frac{110-12a}{5y}
Dividing by 5y undoes the multiplication by 5y.
R=\frac{2\left(55-6a\right)}{5y}
Divide 110-12a by 5y.
-80+5Ry=3\left(10-4a\right)
Use the distributive property to multiply 5 by -16+Ry.
-80+5Ry=30-12a
Use the distributive property to multiply 3 by 10-4a.
30-12a=-80+5Ry
Swap sides so that all variable terms are on the left hand side.
-12a=-80+5Ry-30
Subtract 30 from both sides.
-12a=-110+5Ry
Subtract 30 from -80 to get -110.
-12a=5Ry-110
The equation is in standard form.
\frac{-12a}{-12}=\frac{5Ry-110}{-12}
Divide both sides by -12.
a=\frac{5Ry-110}{-12}
Dividing by -12 undoes the multiplication by -12.
a=-\frac{5Ry}{12}+\frac{55}{6}
Divide -110+5Ry by -12.
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