Solve 5{2+sqrt[3]{64}[6-(-1)^3+4]div2+5(-1)}

$$5 \{ 2 + \sqrt[ 3 ] { 64 } [ 6 - ( - 1 ) ^ { 3 } + 4 ] \div 2 + 5 ( - 1 ) \}$$

Evaluate

$$95$$

Solution Steps

Calculate \sqrt[3]{64} and get 4.

$$5\left(2+\frac{4\left(6-\left(-1\right)^{3}+4\right)}{2}+5\left(-1\right)\right)$$

Calculate -1 to the power of 3 and get -1.

$$5\left(2+\frac{4\left(6-\left(-1\right)+4\right)}{2}+5\left(-1\right)\right)$$

The opposite of -1 is 1.

$$5\left(2+\frac{4\left(6+1+4\right)}{2}+5\left(-1\right)\right)$$

Add 6 and 1 to get 7.

$$5\left(2+\frac{4\left(7+4\right)}{2}+5\left(-1\right)\right)$$

Add 7 and 4 to get 11.

$$5\left(2+\frac{4\times 11}{2}+5\left(-1\right)\right)$$

Multiply 4 and 11 to get 44.

$$5\left(2+\frac{44}{2}+5\left(-1\right)\right)$$

Divide 44 by 2 to get 22.

$$5\left(2+22+5\left(-1\right)\right)$$

Add 2 and 22 to get 24.

$$5\left(24+5\left(-1\right)\right)$$

Multiply 5 and -1 to get -5.

$$5\left(24-5\right)$$

Subtract 5 from 24 to get 19.

$$5\times 19$$

Multiply 5 and 19 to get 95.

$$95$$

Factor

$$5\times 19$$