Solve 5^{3}-4^{-2}div6^-2*3^2+7^2-3^2=

$$5 ^ { 3 } - 4 ^ { - 2 } \div 6 ^ { - 2 } \times 3 ^ { 2 } + 7 ^ { 2 } - 3 ^ { 2 } =$$

Evaluate

$$\frac{579}{4}=144.75$$

Solution Steps

Calculate 5 to the power of 3 and get 125.

$$125-\frac{4^{-2}}{6^{-2}}\times 3^{2}+7^{2}-3^{2}$$

Calculate 4 to the power of -2 and get \frac{1}{16}.

$$125-\frac{\frac{1}{16}}{6^{-2}}\times 3^{2}+7^{2}-3^{2}$$

Calculate 6 to the power of -2 and get \frac{1}{36}.

$$125-\frac{\frac{1}{16}}{\frac{1}{36}}\times 3^{2}+7^{2}-3^{2}$$

Divide \frac{1}{16} by \frac{1}{36} by multiplying \frac{1}{16} by the reciprocal of \frac{1}{36}.

$$125-\frac{1}{16}\times 36\times 3^{2}+7^{2}-3^{2}$$

Multiply \frac{1}{16} and 36 to get \frac{9}{4}.

$$125-\frac{9}{4}\times 3^{2}+7^{2}-3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$125-\frac{9}{4}\times 9+7^{2}-3^{2}$$

Multiply \frac{9}{4} and 9 to get \frac{81}{4}.

$$125-\frac{81}{4}+7^{2}-3^{2}$$

Subtract \frac{81}{4} from 125 to get \frac{419}{4}.

$$\frac{419}{4}+7^{2}-3^{2}$$

Calculate 7 to the power of 2 and get 49.

$$\frac{419}{4}+49-3^{2}$$

Add \frac{419}{4} and 49 to get \frac{615}{4}.

$$\frac{615}{4}-3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{615}{4}-9$$

Subtract 9 from \frac{615}{4} to get \frac{579}{4}.

$$\frac{579}{4}$$

Factor

$$\frac{3 \cdot 193}{2 ^ {2}} = 144\frac{3}{4} = 144.75$$