Solve 5^3-[10+(7-8)^2]-4+2^3

$$5 ^ { 3 } - [ 10 + ( 7 - 8 ) ^ { 2 } ] - 4 + 2 ^ { 3 }$$

Evaluate

$$118$$

Solution Steps

Calculate 5 to the power of 3 and get 125.

$$125-\left(10+\left(7-8\right)^{2}\right)-4+2^{3}$$

Subtract 8 from 7 to get -1.

$$125-\left(10+\left(-1\right)^{2}\right)-4+2^{3}$$

Calculate -1 to the power of 2 and get 1.

$$125-\left(10+1\right)-4+2^{3}$$

Add 10 and 1 to get 11.

$$125-11-4+2^{3}$$

Subtract 11 from 125 to get 114.

$$114-4+2^{3}$$

Subtract 4 from 114 to get 110.

$$110+2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$110+8$$

Add 110 and 8 to get 118.

$$118$$

Factor

$$2\times 59$$