Solve 5^{2}*(4^{3}-3^4div3^2)+(8^3+2^5)=

$$5 ^ { 2 } \cdot ( 4 ^ { 3 } - 3 ^ { 4 } \div 3 ^ { 2 } ) + ( 8 ^ { 3 } + 2 ^ { 5 } ) =$$

Evaluate

$$1919$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 2 from 4 to get 2.

$$5^{2}\left(4^{3}-3^{2}\right)+8^{3}+2^{5}$$

Calculate 5 to the power of 2 and get 25.

$$25\left(4^{3}-3^{2}\right)+8^{3}+2^{5}$$

Calculate 4 to the power of 3 and get 64.

$$25\left(64-3^{2}\right)+8^{3}+2^{5}$$

Calculate 3 to the power of 2 and get 9.

$$25\left(64-9\right)+8^{3}+2^{5}$$

Subtract 9 from 64 to get 55.

$$25\times 55+8^{3}+2^{5}$$

Multiply 25 and 55 to get 1375.

$$1375+8^{3}+2^{5}$$

Calculate 8 to the power of 3 and get 512.

$$1375+512+2^{5}$$

Add 1375 and 512 to get 1887.

$$1887+2^{5}$$

Calculate 2 to the power of 5 and get 32.

$$1887+32$$

Add 1887 and 32 to get 1919.

$$1919$$

Factor

$$19\times 101$$