Solve 5^{circ}2x+5/2x+2x+30^circ+4x-40^circ+2x+50^circ=540^circ

$$5 ^ { \circ } 2 x + \frac { 5 } { 2 } x + 2 x + 30 ^ { \circ } + 4 x - 40 ^ { \circ } + 2 x + 50 ^ { \circ } = 540 ^ { \circ }$$

Solve for x

$$x = \frac{1000}{41} = 24\frac{16}{41} \approx 24.390243902$$

Steps for Solving Linear Equation

Multiply 5 and 2 to get 10.

$$10x+\frac{5}{2}x+2x+30+4x-40+2x+50=540$$

Combine 10x and \frac{5}{2}x to get \frac{25}{2}x.

$$\frac{25}{2}x+2x+30+4x-40+2x+50=540$$

Combine \frac{25}{2}x and 2x to get \frac{29}{2}x.

$$\frac{29}{2}x+30+4x-40+2x+50=540$$

Combine \frac{29}{2}x and 4x to get \frac{37}{2}x.

$$\frac{37}{2}x+30-40+2x+50=540$$

Subtract 40 from 30 to get -10.

$$\frac{37}{2}x-10+2x+50=540$$

Combine \frac{37}{2}x and 2x to get \frac{41}{2}x.

$$\frac{41}{2}x-10+50=540$$

Add -10 and 50 to get 40.

$$\frac{41}{2}x+40=540$$

Subtract 40 from both sides.

$$\frac{41}{2}x=540-40$$

Subtract 40 from 540 to get 500.

$$\frac{41}{2}x=500$$

Multiply both sides by \frac{2}{41}, the reciprocal of \frac{41}{2}.

$$x=500\times \frac{2}{41}$$

Express 500\times \frac{2}{41} as a single fraction.

$$x=\frac{500\times 2}{41}$$

Multiply 500 and 2 to get 1000.

$$x=\frac{1000}{41}$$