Solve 5=(B-A)*1

$$5 = ( B - A ) \cdot 1$$

Solve for A

$$A=B-5$$

Steps for Solving Linear Equation

Divide both sides by 1.

$$5=B-A$$

Swap sides so that all variable terms are on the left hand side.

$$B-A=5$$

Subtract B from both sides.

$$-A=5-B$$

Divide both sides by -1.

$$\frac{-A}{-1}=\frac{5-B}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$A=\frac{5-B}{-1}$$

Divide 5-B by -1.

$$A=B-5$$

Solve for B

$$B=A+5$$

Solution Steps

Divide both sides by 1.

$$5=B-A$$

Swap sides so that all variable terms are on the left hand side.

$$B-A=5$$

Add A to both sides.

$$B=5+A$$