Solve 5=3x^2/2

$$5 = \frac { 3 x ^ { 2 } } { 2 }$$

Solve for x

$$x = \frac{\sqrt{30}}{3} \approx 1.825741858$$

$$x = -\frac{\sqrt{30}}{3} \approx -1.825741858$$

Steps by Finding Square Root

Multiply both sides by 2.

$$5\times 2=3x^{2}$$

Multiply 5 and 2 to get 10.

$$10=3x^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$3x^{2}=10$$

Divide both sides by 3.

$$x^{2}=\frac{10}{3}$$

Take the square root of both sides of the equation.

$$x=\frac{\sqrt{30}}{3} x=-\frac{\sqrt{30}}{3}$$

Steps Using the Quadratic Formula

Multiply both sides by 2.

$$5\times 2=3x^{2}$$

Multiply 5 and 2 to get 10.

$$10=3x^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$3x^{2}=10$$

Subtract 10 from both sides.

$$3x^{2}-10=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 0 for b, and -10 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 3\left(-10\right)}}{2\times 3}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 3\left(-10\right)}}{2\times 3}$$

Multiply -4 times 3.

$$x=\frac{0±\sqrt{-12\left(-10\right)}}{2\times 3}$$

Multiply -12 times -10.

$$x=\frac{0±\sqrt{120}}{2\times 3}$$

Take the square root of 120.

$$x=\frac{0±2\sqrt{30}}{2\times 3}$$

Multiply 2 times 3.

$$x=\frac{0±2\sqrt{30}}{6}$$

Now solve the equation x=\frac{0±2\sqrt{30}}{6} when ± is plus.

$$x=\frac{\sqrt{30}}{3}$$

Now solve the equation x=\frac{0±2\sqrt{30}}{6} when ± is minus.

$$x=-\frac{\sqrt{30}}{3}$$

The equation is now solved.

$$x=\frac{\sqrt{30}}{3} x=-\frac{\sqrt{30}}{3}$$