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5=10x^{2}+\frac{1}{2}\times 50\left(x+0\times 2\right)^{2}
Multiply \frac{1}{2} and 20 to get 10.
5=10x^{2}+25\left(x+0\times 2\right)^{2}
Multiply \frac{1}{2} and 50 to get 25.
5=10x^{2}+25\left(x+0\right)^{2}
Multiply 0 and 2 to get 0.
5=10x^{2}+25x^{2}
Anything plus zero gives itself.
5=35x^{2}
Combine 10x^{2} and 25x^{2} to get 35x^{2}.
35x^{2}=5
Swap sides so that all variable terms are on the left hand side.
x^{2}=\frac{5}{35}
Divide both sides by 35.
x^{2}=\frac{1}{7}
Reduce the fraction \frac{5}{35} to lowest terms by extracting and canceling out 5.
x=\frac{\sqrt{7}}{7} x=-\frac{\sqrt{7}}{7}
Take the square root of both sides of the equation.
5=10x^{2}+\frac{1}{2}\times 50\left(x+0\times 2\right)^{2}
Multiply \frac{1}{2} and 20 to get 10.
5=10x^{2}+25\left(x+0\times 2\right)^{2}
Multiply \frac{1}{2} and 50 to get 25.
5=10x^{2}+25\left(x+0\right)^{2}
Multiply 0 and 2 to get 0.
5=10x^{2}+25x^{2}
Anything plus zero gives itself.
5=35x^{2}
Combine 10x^{2} and 25x^{2} to get 35x^{2}.
35x^{2}=5
Swap sides so that all variable terms are on the left hand side.
35x^{2}-5=0
Subtract 5 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 35\left(-5\right)}}{2\times 35}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 35 for a, 0 for b, and -5 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 35\left(-5\right)}}{2\times 35}
Square 0.
x=\frac{0±\sqrt{-140\left(-5\right)}}{2\times 35}
Multiply -4 times 35.
x=\frac{0±\sqrt{700}}{2\times 35}
Multiply -140 times -5.
x=\frac{0±10\sqrt{7}}{2\times 35}
Take the square root of 700.
x=\frac{0±10\sqrt{7}}{70}
Multiply 2 times 35.
x=\frac{\sqrt{7}}{7}
Now solve the equation x=\frac{0±10\sqrt{7}}{70} when ± is plus.
x=-\frac{\sqrt{7}}{7}
Now solve the equation x=\frac{0±10\sqrt{7}}{70} when ± is minus.
x=\frac{\sqrt{7}}{7} x=-\frac{\sqrt{7}}{7}
The equation is now solved.