Solve for a
a=\frac{35-3c-5b}{8}
Solve for b
b=-\frac{3c}{5}-\frac{8a}{5}+7
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5b+8a+3c=40-5
Subtract 5 from both sides.
5b+8a+3c=35
Subtract 5 from 40 to get 35.
8a+3c=35-5b
Subtract 5b from both sides.
8a=35-5b-3c
Subtract 3c from both sides.
8a=35-3c-5b
The equation is in standard form.
\frac{8a}{8}=\frac{35-3c-5b}{8}
Divide both sides by 8.
a=\frac{35-3c-5b}{8}
Dividing by 8 undoes the multiplication by 8.
5b+8a+3c=40-5
Subtract 5 from both sides.
5b+8a+3c=35
Subtract 5 from 40 to get 35.
5b+3c=35-8a
Subtract 8a from both sides.
5b=35-8a-3c
Subtract 3c from both sides.
5b=35-3c-8a
The equation is in standard form.
\frac{5b}{5}=\frac{35-3c-8a}{5}
Divide both sides by 5.
b=\frac{35-3c-8a}{5}
Dividing by 5 undoes the multiplication by 5.
b=-\frac{3c}{5}-\frac{8a}{5}+7
Divide 35-8a-3c by 5.
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Limits
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