Solve 5+2(3-4(3-3)+5(3-2)+6]-3

$$5 + 2 ( 3 - 4 ( 3 - 3 ) + 5 ( 3 - 2 ) + 6 ] - 3$$

Evaluate

$$30$$

Solution Steps

Subtract 3 from 3 to get 0.

$$5+2\left(3-4\times 0+5\left(3-2\right)+6\right)-3$$

Multiply 4 and 0 to get 0.

$$5+2\left(3-0+5\left(3-2\right)+6\right)-3$$

Subtract 0 from 3 to get 3.

$$5+2\left(3+5\left(3-2\right)+6\right)-3$$

Subtract 2 from 3 to get 1.

$$5+2\left(3+5\times 1+6\right)-3$$

Multiply 5 and 1 to get 5.

$$5+2\left(3+5+6\right)-3$$

Add 3 and 5 to get 8.

$$5+2\left(8+6\right)-3$$

Add 8 and 6 to get 14.

$$5+2\times 14-3$$

Multiply 2 and 14 to get 28.

$$5+28-3$$

Add 5 and 28 to get 33.

$$33-3$$

Subtract 3 from 33 to get 30.

$$30$$

Factor

$$2\times 3\times 5$$